If x(t) = 3t^3 - 4t + 1, then v(t) = 9t^2 - 4.
The points is moving right when v(t) > 0 and left when v(t) < 0.
Determine the time interval on which the point is moving to the right and to the left.
Point P is moving along the x axis so that its position x at time t is given by x=3t^3-4t+1
So I determined the velocity and accleration equations:
v(t) = 3t^2-4
a(t) = 6t
But I have no clue how to determine what time intervals which the point is moving to the right or to the left?