Thread: Integration

Is there a way to do this from the second expression? I ended up where I started from. I do not want to use trigonometrical substitution.

No easy way.

Just stick with trig. sub. ... or (better yet) use hyperbolic substitution.

sec^2(x) - 1 =tan^2(x) . . . . ... . . . cosh^2(x) - 1 = sinh^2(x) .

This is what the question says to do. It must be possible to use the second expression.

Originally Posted by Stuck Man

This is what the question says to do. It must be possible to use the second expression.

Your Original Post gave the impression that you did not want to use trig substitution.

There is one way to solve it without trig substitutiton but it does not involve the second expression.







(This is form)



Note- The identity could also have been used :

I've not seen it before. The question says to use the the two fractions.

Look, stuck man, I donot think there is any way to find the integral from the 2 fractions. Even wolfram alpha solves it using trigonometric substitution. You can see it here if you like. link. If required you can also use hyperbolic substitution.