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Math Help - I don't understand a step in this proof. (Space vectors topic)

  1. #1
    s3a
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    I don't understand a step in this proof. (Space vectors topic)

    The proof I am doing is #7 of the attached pdf.

    For the following (formatting is off from the copy pasting so look at the pdf):
    a2 b = |a2| |b| sin f n = |a| sin q |b| n = |a| |b| sin q n = a b

    How do I go from |a2||b|sin(phi) n to |a| sin(theta)|b| n? It seems that there is an important reason for this step because I would of skipped directly to |a||b|sin(theta)n. Is there something I should not assume that I am assuming? Whether, it is okay for me to skip this step or not, what is going on in the step I would of skipped?

    Any input would be appreciated.
    Thanks in advance!
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    Last edited by s3a; October 15th 2011 at 12:22 PM.
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  2. #2
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    Re: I don't understand a step in this proof. (Space vectors topic)

    Quote Originally Posted by s3a View Post
    The proof I am doing is #7 of the attached pdf.
    For the following (formatting is off from the copy pasting so look at the pdf):
    a2 b = |a2| |b| sin f n = |a| sin q |b| n = |a| |b| sin q n = a b

    How do I go from |a2||b|sin(phi) n to |a| sin(theta)|b| n? It seems that there is an important reason for this step because I would of skipped directly to |a||b|sin(theta)n. Is there something I should not assume that I am assuming? Whether, it is okay for me to skip this step or not, what is going on in the step I would of skipped?

    Any input would be appreciated.
    Thanks in advance!
    There is no attached PDF.
    The formatting makes the question impossible to read.
    Please redo (edit) this posting.
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  3. #3
    s3a
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    Re: I don't understand a step in this proof. (Space vectors topic)

    Oops! I attached it now. Also, I'm circling in red the step that confuses me.

    Basically, I would of just skipped to the right side of the equal sign right after the red circling and the question is in the first post.
    Attached Thumbnails Attached Thumbnails I don't understand a step in this proof. (Space vectors topic)-q7.jpeg  
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