Hi everyone,

Could someone please explain to me how to solve the integral x^3-x^2-x+1/(x^2+9)

I know that I have to do long divition first.

After doing this I got x-1-10x+10/x^2+9, but the correct answer for this step is x-1-8x-1/x^2+9. Does anyone see where I went wrong?

After that I am supposed to use a table and the correct answer is

1/2x^2-x-8(1/2ln(x^2+9))+8(1/3tan^-1(x/3))+c

Can someone explain to me how they got this as their final answer, please?

Thank you very much