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Thread: Improper Integral

  1. October 11th 2011, 09:55 AM #1
    sjmiller
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    Improper Integral

    Hi,

    \int_{-1}^8 \frac{1}{x^{2/3}} \, dx

    How is this even possible since the integrand isn't even defined for values less than 0?...
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  2. October 11th 2011, 10:03 AM #2
    Plato
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    Re: Improper Integral

    Quote Originally Posted by sjmiller View Post
    \int_{-1}^8 \frac{1}{x^{2/3}} \, dx
    How is this even possible since the integrand isn't even defined for values less than 0?
    Why would you say that?
    For all x\ne 0 we have \frac{1}{x^{2/3}}>0.
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