# Improper Integral

• Oct 11th 2011, 09:55 AM
sjmiller
Improper Integral
Hi,

$\int_{-1}^8 \frac{1}{x^{2/3}} \, dx$

How is this even possible since the integrand isn't even defined for values less than 0?...
• Oct 11th 2011, 10:03 AM
Plato
Re: Improper Integral
Quote:

Originally Posted by sjmiller
$\int_{-1}^8 \frac{1}{x^{2/3}} \, dx$
How is this even possible since the integrand isn't even defined for values less than 0?

Why would you say that?
For all $x\ne 0$ we have $\frac{1}{x^{2/3}}>0$.