Velocity and Acceleration for a Trig equation
A particle moves in a straight line along the x-axis so that its position, x(t), at time t seconds, t≥0, is given by x=sin(pi.t^2)
a) Find expressions for the velocity and acceleration of the particle at time t
b) Find the times for which the particle is stationary
If anyone could help with this question, that would be great
Re: Velocity and Acceleration for a Trig equation
Do you know the definitions of velocity and acceleration?
Re: Velocity and Acceleration for a Trig equation
I think velocity will just be the derivative, however I have forgotten what acceleration will be
Re: Velocity and Acceleration for a Trig equation
Quote:
Originally Posted by
gbooker
I think velocity will just be the derivative, however I have forgotten what acceleration will be
Acceleration is the second derivative of displacement (or the first derivative of velocity)
Re: Velocity and Acceleration for a Trig equation
ok so as a result of that the derivative (velocity) = (cos.pi.x^2). (2x.pi)
so does that mean for part b is it just solve for when velocity=0?
Re: Velocity and Acceleration for a Trig equation
Quote:
Originally Posted by
gbooker
ok so as a result of that the derivative (velocity) = (cos.pi.x^2). (2x.pi)
so does that mean for part b is it just solve for when velocity=0?
yes,  = 2\pi t \cdot \cos(\pi t^2) = 0)
solve for those values of
that make the velocity zero.