hi,
i need to work out the gradient at following points at the given curve:
y=3x^2-4x+1 at x=1
i know how to start it but after that im stuck and require some help, please!
i can do this:
dy/dy= 6x-4
The equation of a straight line is $\displaystyle y = mx+c$ where m is the gradient and c the y intercept. You've worked out that $\displaystyle m = 2$ so you have something of the form $\displaystyle y = 2x+c$.
To find c (the y intercept) sub in your point $\displaystyle (1,0)$ into $\displaystyle y = 2x+c$ and solve for c.
Spoiler: