hi,

i need to work out the gradient at following points at the given curve:

y=3x^2-4x+1 at x=1

i know how to start it but after that im stuck and require some help, please!

i can do this:

dy/dy= 6x-4

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- October 7th 2011, 10:05 AMandyboy179gradient at following points at the given curve?
hi,

i need to work out the gradient at following points at the given curve:

y=3x^2-4x+1 at x=1

i know how to start it but after that im stuck and require some help, please!

i can do this:

dy/dy= 6x-4 - October 7th 2011, 10:13 AMskeeterRe: gradient at following points at the given curve?
- October 7th 2011, 10:17 AMandyboy179Re: gradient at following points at the given curve?
sorry that was a typo! dy/dx means the gradient

- October 7th 2011, 10:24 AMskeeterRe: gradient at following points at the given curve?
- October 7th 2011, 11:00 AMandyboy179Re: gradient at following points at the given curve?
6x1-4 so, 6-4=2

- October 7th 2011, 11:21 AMandyboy179Re: gradient at following points at the given curve?
gradient = 2

- October 7th 2011, 11:23 AMskeeterRe: gradient at following points at the given curve?
- October 7th 2011, 11:25 AMandyboy179Re: gradient at following points at the given curve?
but then what else do i do to find the equation of the tangent to y=3x^2-4x+1 parallel to y=2x+7??

- October 7th 2011, 11:44 AMe^(i*pi)Re: gradient at following points at the given curve?
- October 7th 2011, 11:53 AMandyboy179Re: gradient at following points at the given curve?
no im not sure how to do this.

- October 7th 2011, 12:37 PMe^(i*pi)Re: gradient at following points at the given curve?
- October 7th 2011, 12:50 PMandyboy179Re: gradient at following points at the given curve?
ok so would i do:

y= 3-4+1

y= 0? - October 7th 2011, 01:17 PMe^(i*pi)Re: gradient at following points at the given curve?
- October 7th 2011, 01:27 PMandyboy179Re: gradient at following points at the given curve?
im not sure how to do this next step. i can do the equation of a straight line but i only have one set of brackets which is (1,0) what do i do?

- October 7th 2011, 01:36 PMe^(i*pi)Re: gradient at following points at the given curve?