Just try fittin in iota in your calculus equations.

eg. x^2 = - (ix)^2

you can then use e^i@ = cos(@) + i sin(@)

formula to find the answer.

try it this idea is a serious whirlwind.

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- Feb 15th 2006, 07:14 AMabuTry iota
Just try fittin in iota in your calculus equations.

eg. x^2 = - (ix)^2

you can then use e^i@ = cos(@) + i sin(@)

formula to find the answer.

try it this idea is a serious whirlwind. - Feb 15th 2006, 07:21 AMMathGuruSerious?
Can you further explain what you are trying to say here?

- Feb 15th 2006, 09:43 AMCaptainBlackQuote:

Originally Posted by**MathGuru**

problems simpler.

RonL - Feb 15th 2006, 09:46 AMMathGuru
have you ever heard of i being referred to as iota?

- Feb 15th 2006, 10:29 AMCaptainBlackQuote:

Originally Posted by**MathGuru**

RonL - Feb 15th 2006, 10:45 AMMathGuruiota
I think abu is from India (I looked up the IP address), but ok.

- Feb 16th 2006, 06:59 AMabuYes I Am An Indian
Yes i am saying it makes problemz simpler, you can also use it if u dont remember a formula etc.

for example (let | be the integration sign)

| root of(a^2 - x^2) dx = | root of(x^2 + a^2) dx

this worx as i is not dependent on x

but is i a const? - Feb 16th 2006, 08:51 AMCaptainBlackQuote:

Originally Posted by**abu**

but:

$\displaystyle

\int \sqrt(-x^2)\ dx=\int \sqrt(x^2)\ dx

$

so:

$\displaystyle

i\ \int |x| dx = \int |x| dx

$

which is**false**even if we throw in a random $\displaystyle \pm$ sign or two

RonL - Feb 16th 2006, 10:37 AMdud
Cut and paste from wikipedia:

"The lowercase Iota symbol is sometimes used to write the imaginary unit but more often latin i or latin j are used."

Sounds good to me! :p