Thread: Defferentiation

rocks are filling a cone at 72in^3 per min. during every interval of time the cone has a height, h, which is always 6 times the radius. what is the rate of change of the radius of the cone at the instant when the radius is 2in. the volume of the cone is
v=1/3 pie r^2 h.

Originally Posted by leeubc22

rocks are filling a cone at 72in^3 per min. during every interval of time the cone has a height, h, which is always 6 times the radius. what is the rate of change of the radius of the mound at the instant when the radius is 2in. the volume of the cone is
v=1/3 pie r^2 h.

simplify the volume equation, then take the derivative w/r to time. substitute in your given values and determine the value of

btw, the greek letter is spelled pi ... "pie" is something you eat.

haha thanks. i was in a rush and wasn't paying attention