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Math Help - Defferentiation

  1. #1
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    Defferentiation

    rocks are filling a cone at 72in^3 per min. during every interval of time the cone has a height, h, which is always 6 times the radius. what is the rate of change of the radius of the cone at the instant when the radius is 2in. the volume of the cone is
    v=1/3 pie r^2 h.
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  2. #2
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    Re: Defferentiation

    Quote Originally Posted by leeubc22 View Post
    rocks are filling a cone at 72in^3 per min. during every interval of time the cone has a height, h, which is always 6 times the radius. what is the rate of change of the radius of the mound at the instant when the radius is 2in. the volume of the cone is
    v=1/3 pie r^2 h.
    h = 6r

    V = \frac{\pi}{3} r^2 \cdot (6r)

    simplify the volume equation, then take the derivative w/r to time. substitute in your given values and determine the value of \frac{dr}{dt}

    btw, the greek letter \pi is spelled pi ... "pie" is something you eat.
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  3. #3
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    Re: Defferentiation

    haha thanks. i was in a rush and wasn't paying attention
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