suppose (x^2/26)+(y^2/64)=1 and y(1)=7.88811 Find y'(1) by implicit diffentiation
I get y'=16x/9y but I'm not sure where to go from there to get y'(1)?
Sorry I typoed
Should have been
(x^2/36)+(y^2/64)=1
Forgive me, but I'm just not making a connection between the information y(1)=7.88811 and the original equation. I know I need to substitue and solve for x, but there's a point in my brain that doesnt want to accept how this should occur.
is it just plug in 7.88811 for y^2 and solve for x?