Hello guys, im new here, this seems like a nice forum to help me catch up on my math I havent been doing math for years and now I started uni and I got a lot to catch up.
I cant seem to manage to get the math format in so I apologize in advance for the confusing syntex
So I got a couple of questions I did not manage to get past in complex numbers.
If you could explain how to break it down to a newbie i would be in your debt,
give the trigonometric form [(r=cos(theta) + isin(theta)] of:
(1-sqrt(3i))^4
when i break it down the long way i get to
=-8-21*sqrt(2)+18i-4*sqrt(3i)
and from there its a prety dead end, r= 222*sqrt(2) which i believe is probably incorrect
the other problem is a little simpler but I got stuck with the isin value
sqrt(3)+3i
now i broke it down to r = 2*sqrt(3)
and from there cos(theta)=sqrt(3)/2*sqrt(3) * sqrt(3)/sqrt(3) = 1/2
but for the isin i cant get past the isin=3/2sqrt(3)
how do i get rid of this pesky square root 3? i know that it is either positive or negative sqrt(3)/2 according to the unit circle, but how do i find which?
Thanks a bunch
Yshipping