Please help me with this limit problem:
limit as x approaches 1 of: (x^4-1)/(x^3-1)
I factored the top to be (x^2-1)(x^2+1) and the bottom using difference of cubes which I got to be (x-1)(x^2+x+1)
I am stuck at this point because nothing seems to cancel out and I dont see any more factors. So does it not exist?