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Math Help - Triple integral - solving issue

  1. #1
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    Triple integral - solving issue

    Hello, I've got a problem which I am just stuck with..:

    [Triple integral]D x^2+y^2 dxdydz, where D: 0<=x^2+y^2<=z^2 , 0<=z<=1

    I have tried with spherical coordinates and other stuff(/tricks). I think my problem maybe is in dealing with the intervals. Could somebody please help me with at least some hints?

    Sorry if there is something missing in my post. This is my first post on this forum. hehe

    Thanks in advance!
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  2. #2
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    Re: Triple integral - solving issue

    Are you clear that D is just a circular cone with a = 1 and h = 1? Cylindrical...

    z is going...

    from z = r (the side of the cone) up to z = 1 (the base)

    ... for every bit that r is going...

    from zero (the z axis) along to as far as where r = z = 1

    ... for every bit that theta is going right round (zero to 2 pi).

    And your integrand is r(x^2 + y^2) = r^3.
    Last edited by tom@ballooncalculus; September 30th 2011 at 06:14 AM. Reason: typo
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  3. #3
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    Re: Triple integral - solving issue

    Yes, cylindrical coordinates is the way to go.
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  4. #4
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    Re: Triple integral - solving issue

    Thank you! Solved it!
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