# Vector parametrization of a circle.

• Sep 29th 2011, 08:50 PM
Bracketology
Vector parametrization of a circle.
EDIT

Or Better yet. How would I solve a random curve, for example. x=-3z^2?

x(t)=
y(t)=
z(t)=

This would probably help me a little more.

Why is the answer for this one <0,0,0>?
• Sep 29th 2011, 10:41 PM
mr fantastic
Re: Vector parametrization of a circle.
Quote:

Originally Posted by Bracketology
EDIT

Or Better yet. How would I solve a random curve, for example. x=-3z^2?

x(t)=
y(t)=
z(t)=

This would probably help me a little more.

Why is the answer for this one <0,0,0>?

What you have posted makes no sense. Instead of making up questions and giving answers that mean nothing, please post, in it's entirety, the question you need help with.

For what it's worth - very liitle, I'll guess - the example you have invented can be parametrised as

x = -3t^2
z = t.

Since you have not given endpoints to the curve, it's impossible to give a domain for t. I have no idea how <0, 0, 0> is meant to relate to it.