Hello,
Can you please verify if my answer is correct?
Answer:n-2/4^n
Since the problem asks two questions, and you have only one answer, it is obvious that your answer is NOT correct.
And, in case you think I am being picky, what you give not the correct answer to either question. Perhaps if you showed how you got that we could point out errors.
I just needed help with finding the solution for the first part. Which is find a(subscript)n.
Here's what I got so far... I realize I did the first part wrong, here's where i'm stuck tho:
(6-n/4^n) - (6-(n+1)/4^(n+1))
(6(4^n)-n/4^n) - (6(4^(n-1)) - n + 1)/4^(n-1)
....
Where do I go from here?
No, it's the other way around. You want $\displaystyle S_{n+1}- S_n$.
$\displaystyle \frac{6- (n+1)}{4^{n+1}}- \frac{6- n}{4^n}$(6(4^n)-n/4^n) - (6(4^(n-1)) - n + 1)/4^(n-1)
$\displaystyle \frac{6}{4(4^n)}- \frac{n}{4(4^n)}- \frac{1}{4(4^n)}- \frac{6}{4^n}+ \frac{n}{4^n}$
$\displaystyle \frac{6}{4(4^n)}- \frac{24}{4(4^n)}- \left(\frac{n}{4(4^n)}- \frac{4n}{4(4^n}\right)- \frac{1}{4(4^n)}$.
....
Where do I go from here?