not really sure where to start on this. Basically trying to find the indefinite integral of 3/(2x-x^2)^0.5 can't really figure out what I should do here, I don't think I can substitute and ibp.
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Rewrite the denominator as: $\displaystyle \sqrt{2x-x^2}=\sqrt{\frac{x^2-2x}{-1}}=\sqrt{\frac{(x-1)^2-1}{-1}}=\sqrt{1-(x-1)^2}$ Now, you should recognize an arcsin by using a handy substitution ...
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