Originally Posted by

**Prove It** I have now had to waste two posts telling you how to go about answering your question because I have tried to translate (wrongly) what you have written. I suggest you learn some basic LaTeX so that you can avoid frustrating the people here who are trying to help you.

Now, assuming that your integral is $\displaystyle \displaystyle \int{-\frac{4}{3}\left(x^{-3} - 1\right)\,dx}$...

$\displaystyle \displaystyle \begin{align*} \int{-\frac{4}{3}\left(x^{-3} - 1\right)\,dx} &= -\frac{4}{3}\int{x^{-3} - 1\,dx} \end{align*}$

Now integrate that stuff term by term using the rule you know $\displaystyle \displaystyle \int{x^n\,dx} = \frac{1}{n + 1}x^{n+1}$. It doesn't make any difference if your exponent is negative (except if your exponent is -1).