Lim x approaches 0 [(√x+4)-2]/x I believe you multiply by the conjugate of √ but i'm getting lost on the algebra. Thanks for your help!
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$\displaystyle \frac{\sqrt{x+4}-2}{x}=\frac{(\sqrt{x+4}-2)(\sqrt{x+4}+2)}{x(\sqrt{x+4}+2)}=\frac{x}{ x(\sqrt{x+4}+2) }=\ldots$
Thanks 1/4 got it
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