# Math Help - change of base?

1. ## change of base?

I am just learning Log equations

How does $4^x$^2 $*2^3^x=4$

become X= $\frac{1}{2}$, 2

2. ## Re: change of base?

I assume it's $4^{x^2}\cdot2^{3x}=4$. This is equivalent to
$(2^2)^{x^2}\cdot2^{3x}=2^2$
$2^{2x^2}\cdot2^{3x}=2^2$
$2^{2x^2+3x}=2^2$
$2x^2+3x=2$