I am just learning Log equations

How does $\displaystyle 4^x$^2$\displaystyle *2^3^x=4$

become X=$\displaystyle \frac{1}{2}$, 2

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- Sep 20th 2011, 04:38 AMdelgeezeechange of base?
I am just learning Log equations

How does $\displaystyle 4^x$^2$\displaystyle *2^3^x=4$

become X=$\displaystyle \frac{1}{2}$, 2 - Sep 20th 2011, 04:49 AMemakarovRe: change of base?
I assume it's $\displaystyle 4^{x^2}\cdot2^{3x}=4$. This is equivalent to

$\displaystyle (2^2)^{x^2}\cdot2^{3x}=2^2$

$\displaystyle 2^{2x^2}\cdot2^{3x}=2^2$

$\displaystyle 2^{2x^2+3x}=2^2$

$\displaystyle 2x^2+3x=2$