change of base?

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September 20th 2011, 04:38 AM
delgeezee

change of base?

I am just learning Log equations

How does $4^x$ ^2 $*2^3^x=4$

become X= $\frac{1}{2}$ , 2
September 20th 2011, 04:49 AM
emakarov

Re: change of base?

I assume it's $4^{x^2}\cdot2^{3x}=4$ . This is equivalent to
$(2^2)^{x^2}\cdot2^{3x}=2^2$
$2^{2x^2}\cdot2^{3x}=2^2$
$2^{2x^2+3x}=2^2$
$2x^2+3x=2$

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