Limit as x approaches -1 [(1) / (x+1) - (3) / (X^2+5x+4)] I have since learned that the answer is -1/3 but have no idea how, any one got any suggestions?
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Originally Posted by zocheyado Limit as x approaches -1 [(1) / (x+1) - (3) / (X^2+5x+4)] $\displaystyle \frac{1}{x+1}-\frac{3}{x^2+5x+4}=\frac{x^2+2x+1}{(x+1)(x^2+5x+4) }=\frac{(x+1)^2}{(x+1)^2(x+4)}=\ldots$
SO how do you go from step 1 to step b? that is my issue.
Originally Posted by zocheyado SO how do you go from step 1 to step b? that is my issue. If the correct reading is $\displaystyle \frac{1}{x+1}-\frac{3}{x^2+5x+4}$ the factor and combine $\displaystyle \frac{1}{(x+1)}-\frac{3}{(x+1)(x+4)}$
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