Can someone please tell me if I am doing this problem properly? e^2x-3e^x+2=0 ln2=ln3e^x-lne^2x ln2=(ln3e^x)/(lne^2x) ln2=ln3e^-x ln2=-xln3e (lne cancels) ln2=-3x and then solving for x to get -.23
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Your second line is wrong. This is how I would approach the problem: Let A = e^x. Then you have A^2 - 3A + 2 = 0 Factor to solve for A, then convert this to a solution involving x.
Let,
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