Can someone please tell me if I am doing this problem properly?
ln2=-xln3e (lne cancels)
ln2=-3x and then solving for x to get -.23
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Your second line is wrong.
This is how I would approach the problem:
Let A = e^x. Then you have
A^2 - 3A + 2 = 0
Factor to solve for A, then convert this to a solution involving x.
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