# Help with natural logarithms

• Sep 18th 2011, 03:59 PM
jmanna98
Help with natural logarithms
Can someone please tell me if I am doing this problem properly?

e^2x-3e^x+2=0

ln2=ln3e^x-lne^2x

ln2=(ln3e^x)/(lne^2x)

ln2=ln3e^-x

ln2=-xln3e (lne cancels)

ln2=-3x and then solving for x to get -.23
• Sep 18th 2011, 04:05 PM
TheChaz
Re: Help with natural logarithms