Hi,
If anyone can help pls
The formula for change of base is logbz = 1/ log z b
Use this formula to solve logz5 + log5Z =2
thank you
i don't see your problem here. you were given the formula to use
$\displaystyle \log_z 5 + \log_5 z = 2$
$\displaystyle \Rightarrow \frac {1}{\log_5 z} + \log_5 z = 2$
$\displaystyle \Rightarrow \left( \log_5 z \right)^2 - 2 \log_5 z + 1 = 0$
the above is quadratic in $\displaystyle \log_5 z$. now continue