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Thread: Change of base

  1. September 11th 2007, 11:44 PM #1
    bungy189
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    Change of base

    Hi,

    If anyone can help pls

    The formula for change of base is logbz = 1/ log z b


    Use this formula to solve logz5 + log5Z =2

    thank you
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  2. September 12th 2007, 12:02 AM #2
    Jhevon
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    Quote Originally Posted by bungy189 View Post
    Hi,

    If anyone can help pls

    The formula for change of base is logbz = 1/ log z b


    Use this formula to solve logz5 + log5Z =2

    thank you
    i don't see your problem here. you were given the formula to use

    \log_z 5 + \log_5 z = 2

    \Rightarrow \frac {1}{\log_5 z} + \log_5 z = 2

    \Rightarrow \left( \log_5 z \right)^2 - 2 \log_5 z + 1 = 0

    the above is quadratic in \log_5 z. now continue
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