Hi,

If anyone can help pls

The formula for change of base islogbz= 1/logzb

Use this formula to solvelogz5 + log5Z =2

thank you

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- Sep 11th 2007, 11:44 PMbungy189Change of base
Hi,

If anyone can help pls

The formula for change of base is**log**bz**= 1/****log**z**b**

Use this formula to solve**log**z**5 + log**5**Z =2**

thank you - Sep 12th 2007, 12:02 AMJhevon
i don't see your problem here. you were given the formula to use

$\displaystyle \log_z 5 + \log_5 z = 2$

$\displaystyle \Rightarrow \frac {1}{\log_5 z} + \log_5 z = 2$

$\displaystyle \Rightarrow \left( \log_5 z \right)^2 - 2 \log_5 z + 1 = 0$

the above is quadratic in $\displaystyle \log_5 z$. now continue