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Math Help - Derivatives: Finding a dervative, with a given cordinate

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    Question Derivatives: Finding a dervative, with a given cordinate

    Find an equation of the tangent line to the at the given point (1,1)
    y= squareroot( x)

    What I tried to do:

    Lim f(x) - (a) -> lim square root (x) - (1)
    x->a x-a x->1 (x)-1

    I don't know what to do because there is an answer, and what I tried to do makes it 0/0 which is bad.

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  2. #2
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    Re: Derivatives: Finding a dervative, with a given cordinate

    Quote Originally Posted by SaltyBriefs View Post
    Find an equation of the tangent line to the at the given point (1,1)
    y= squareroot( x)

    What I tried to do:

    Lim f(x) - f(a) -> lim square root (x) - (1)
    x->a x-a x->1 (x)-1

    correction

    f'(1) = \lim_{x \to 1} \frac{\sqrt{x} - \sqrt{1}}{x - 1}

    f'(1) = \lim_{x \to 1} \frac{\sqrt{x} - 1}{x - 1}

    f'(1) = \lim_{x \to 1} \frac{\sqrt{x} - 1}{(\sqrt{x} - 1)(\sqrt{x} + 1)}

    finish it?
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