Find an equation of the tangent line to the at the given point (1,1)

y= squareroot( x)

What I tried to do:

Limf(x) - (a)-> limsquare root (x) - (1)

x->a x-a x->1 (x)-1

I don't know what to do because there is an answer, and what I tried to do makes it 0/0 which is bad.