could you explain what is y?
The volume of Solid S should be 18h*b^2,
The volume of a pyramid is 1/3 * Base Area * Height
Find the volume V of the described solid S. A pyramid with height 3h and a rectangular base with dimensions 3b and 6b.
So I found the following: 3b[1-y/3h) and 6b(1-y/3h) --> Which I belive is where the error is coming from because I cant seem to get the correct answer.
Integral from a=0,b=h of 18h^2(1-y/3h)^2 dy
= from 0 to h of y - 2/3h(1/2)y^2 + 1/9h^2(1/3)y^3
= 38/3b^2h
Thanks in advance.