Lim where f (x) = 2 (x+1) if x <3

x->2 4 if x=3

x^2 - 1 if x> 3

please tell me you have to write out what the left and right limits are to find out if they are equal?

:(

left limit is 6 and right is 3 so the answer is DNE right?!

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- September 16th 2011, 12:55 PMhabibixoxLimits of piecewise function
Lim where f (x) = 2 (x+1) if x <3

x->2 4 if x=3

x^2 - 1 if x> 3

please tell me you have to write out what the left and right limits are to find out if they are equal?

:(

left limit is 6 and right is 3 so the answer is DNE right?! - September 16th 2011, 12:59 PMskeeterRe: Limits of piecewise function
If , then does not exist.

- September 16th 2011, 09:02 PMProve ItRe: Limits of piecewise function
- September 17th 2011, 04:26 AMHallsofIvyRe: Limits of piecewise function
If, in fact, you are trying to find the limit at 2 then you can ignore everything that is not close to 2. In particular, f(x)= 2(x+ 1) for x "anywhere near 2" (close to 2 is certainly less than 3). You do NOT use " " to evaluate since that is true only for x> 3.

- September 17th 2011, 08:21 AMhabibixoxRe: Limits of piecewise function
yes

- September 17th 2011, 08:22 AMhabibixoxRe: Limits of piecewise function
why wouldnt you test out the limits?

- September 17th 2011, 08:45 AMhabibixoxRe: Limits of piecewise function
would i be completely wrong if i showed what i did at first on a quiz?

i showed how the right limit doesn't = the left limit so i wrote in conclusion the limit doesn't exist because 3 is not equal to 6 - September 17th 2011, 11:05 AMskeeterRe: Limits of piecewise function

note that ...

- September 17th 2011, 02:40 PMHallsofIvyRe: Limits of piecewise function