Calculate The Following Integral
Hello! The problem is:
Calculate The Following Integral:
(e^x + e^-x) from ln2 to ln3.
I'm pretty sure the next step is to change it to (e^x - e^-x) as those are the anti-derivatives right? Or maybe I'm starting horrible hence why I can't solve it.
Thanks in advance for any help! I've been stuck only on this one problem for hours!
re: Calculate The Following Integral
Quote:
Originally Posted by
antz215
Hello! The problem is:
Calculate The Following Integral:
(e^x + e^-x) from ln2 to ln3.
I'm pretty sure the next step is to change it to (e^x - e^-x) as those are the anti-derivatives right?
You can always find help here.
Know that }=3~\&~e^{-\ln(3)}=\frac{1}{3}~.)
re: Calculate The Following Integral
re: Calculate The Following Integral
From both helps I am getting:
e^x + e^-x dx
(e^x - e^-x)
(e^ln3 - e^-ln3) - (e^ln2 - e^-ln2)
3 - 1/3 - 2 + 1/2
= 7/6
I think that is correct? Thanks for your guys' help!
Re: Calculate The Following Integral
Yes, that is correct. Congratulations!