Another Directional Derivative

I'm new at working with directional derivatives. I'm stuck on this problem. Would someone mind helping me with the "Point" and "Direction" parts of the problem. I'm just looking for a place to start, not for someone to do the problem for me. Thanks.

*In each of the following, find the directional derivative of f at P in the given direction.*

1. f(x,y)=xy(1-x^2-y^2), P=any point on the unit circle, Direction: in the direction of **OP**.

I found that the gradient of f is: <y(1-x^2-y^2)-2yx^2, x(1-x^2-y^2)-2xy^2>, so I'm stuck on finding P and the direction.

Re: Another Directional Derivative

Quote:

Originally Posted by

**dbakeg00** *In each of the following, find the directional derivative of f at P in the given direction.*

1. f(x,y)=xy(1-x^2-y^2), P=any point on the unit circle, Direction: in the direction of **OP**.

I found that the gradient of f is: <y(1-x^2-y^2)-2yx^2, x(1-x^2-y^2)-2xy^2>, so I'm stuck on finding P and the direction.

If $\displaystyle P: (a,b)$ then $\displaystyle \overrightarrow {OP}=<a,b> $ and you know that $\displaystyle a^2+b^2=1$.

Re: Another Directional Derivative

Ok, I did the problem, would you mind checking for me? Thanks

So I changed [the format] of f (x,y) = (xy-x^3y-xy^3)

and P=(a,b) & **OP**=<a,b>

Now I have the gradient of f=<y-3x^2y-y^3, x-x^3-3xy^2>

D**u**f(x,y)=(a)(y-3x^2y-y^3)+(b)(x-x^3-3xy^2)

D**u**f(a,b)=(a)(b-3a^2b-b^3)+(b)(a-a^3-3ab^2)

D**u**f(a,b)= (ab-3a^3b-ab^3) + (ab-a^3b-3ab^3)

D**u**f(a,b)= 2ab-4a^3b-4ab^3

D**u**f(a,b)= ab-2a^3b-2ab^3

D**u**f(a,b)= ab(1-2a^2-2b^2)