Can you give me hint...Where to start ?

I want to find constant a for function

((ax^2 - 6x + 4)/(x^2 - x - 2))

when lim x to 2...

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- September 12th 2011, 12:36 PMFranciscusfinding constant a
Can you give me hint...Where to start ?

I want to find constant a for function

((ax^2 - 6x + 4)/(x^2 - x - 2))

when lim x to 2... - September 12th 2011, 12:46 PManonimnystefyRe: finding constant a
hi

you should post the whole question for us to help you.from here we cannot do anything. - September 12th 2011, 12:56 PMCaptainBlackRe: finding constant a
- September 12th 2011, 01:03 PMFranciscusRe: finding constant a
Find a value for constant a in a function f(x) = ((ax^2 - 6x + 4) divided (x^2 - x - 2)) so that the limit exists, when the x approaches 2.

- September 12th 2011, 02:10 PMFranciscusRe: finding constant a
Thanks for quick answer CB. Yes I meant finite. I'm from Finland, so I'm not familiar with all the notions.

So in denominator I got (x-2)(x+1). Can I use these values for x in numerator or do I have to factor it other way to find out a? - September 12th 2011, 08:15 PMCaptainBlackRe: finding constant a
- September 13th 2011, 09:26 AMFranciscusRe: finding constant a
Thanks. Great forum!