finding constant a

Can you give me hint...Where to start ?

I want to find constant a for function

((ax^2 - 6x + 4)/(x^2 - x - 2))

when lim x to 2...

hi

you should post the whole question for us to help you.from here we cannot do anything.

Quote:

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Originally Posted by Franciscus

Can you give me hint...Where to start ?

I want to find constant a for function

((ax^2 - 6x + 4)/(x^2 - x - 2))

when lim x to 2...

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What have you done?

I presume you want the limit as x approaches 2 to be finite?

If so you need (x-2) to be a factor of the numerator (it is already a factor of the denominator).

CB

Find a value for constant a in a function f(x) = ((ax^2 - 6x + 4) divided (x^2 - x - 2)) so that the limit exists, when the x approaches 2.

Thanks for quick answer CB. Yes I meant finite. I'm from Finland, so I'm not familiar with all the notions.

So in denominator I got (x-2)(x+1). Can I use these values for x in numerator or do I have to factor it other way to find out a?

Quote:

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Originally Posted by Franciscus

Thanks for quick answer CB. Yes I meant finite. I'm from Finland, so I'm not familiar with all the notions.

So in denominator I got (x-2)(x+1). Can I use these values for x in numerator or do I have to factor it other way to find out a?

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As I said you need to be a factor of the numerator (to cancel the factor in the denominator)

For to be a factor of the numerator you need

CB

Thanks. Great forum!