1. limit of exponent type

$lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}}$

i get here $1^{\infty}$ form which states thats its some sort of exponent

2. Re: limit of exponent type

Originally Posted by transgalactic
$lim_{x->0^{+}}(1+sinx)^{\frac{1}{\sqrt{x}}}$

i get here $1^{\infty}$ form which states thats its some sort of exponent
$1^{\infty}$ is one of the indeterminate forms that you can use L'hopital's rule on

3. Re: limit of exponent type

lhopital is used on fraction here is exponent

4. Re: limit of exponent type

Originally Posted by transgalactic
lhopital is used on fraction here is exponent
$y = (1+\sin{x})^{\frac{1}{\sqrt{x}}}$

$\ln{y} = \frac{\ln(1+\sin{x})}{\sqrt{x}}}$

5. Re: limit of exponent type

why cant i use the exponent definition
?