derivates

**lilheadbaby1** · February 13th 2006, 12:12 PM

Find the derivate of p(x)= (3x)^1/2
using the alternative formula for the derivate
f ' (x)= lim f(z)-f(x)/z-x
z>x

my answer was 1/2(3x)^1/2
but its wrong

**CaptainBlack** · February 13th 2006, 01:48 PM

Originally Posted by lilheadbaby1

Find the derivate of p(x)= (3x)^1/2
using the alternative formula for the derivate
f ' (x)= lim f(z)-f(x)/z-x
z>x

my answer was 1/2(3x)^1/2
but its wrong

$\frac{f(z)-f(x)}{z-x}=\frac{(3z)^{1/2}-(3x)^{1/2}}{z-x}$

$ =(3z)^{1/2}\frac{(1-(x/z)^{1/2})}{z(1-x/z)} $

$ =\left( \frac{3}{z} \right)^{1/2} \frac{1-(x/z)^2}{(1+(x/z)^{1/2})(1-(x/z)^{1/2})}$

$ =\left( \frac{3}{z} \right)^{1/2} \frac{1}{(1+(x/z)^{1/2})}$

So:
$ \lim_{z \rightarrow x}\frac{f(z)-f(x)}{z-x}=\left( \frac{3}{x} \right)^{1/2} \frac{1}{2}= \frac{\sqrt{3}}{2} x^{-1/2} $

RonL

Thread: derivates

LinkBack

Thread Tools

Display

derivates

Similar Math Help Forum Discussions

Derivates and their graphs

Using first/second derivates

Derivates Question

Natural log and derivates

Induction with derivates

Search Tags