there is a continues and positive f in [0,1]
prove that g(x) is not integrabile in [0,1]
g(x)=f(x) for rational x
g(x)=-f(x) for irational x
why its not integrible?
because f the endless points of disconinuety?
my prof showed a function
g(x)=1 for rational x
g(x)=1/x for irational x
and he said that it is integrible
i dont know why the original is not integrible