## eeexistence of cas a resolt

3)b)
prove that for all $\displaystyle 0<c<\frac{{1}}{2}$ there is x>0 so $\displaystyle \frac{1}{x}-\frac{1}{e^{x}-1}=c$

my try:
looks like the meen value theory here but i dont know what functions to take
?