Originally Posted by
celtic1234 Hi all
Is my solution correct?
Evaluate "integration sign" [(2e^x)-SQRT(x)] between limits b=10 and a=1.
Integrating each tem separately:
2e^x.dx,
re-arranging: e^x.2.dx................(1)
let u=x, du=1.dx, 2du=2dx
substituting u=x and 2du=2dx back into (1) gives
(e^u). 2du
Integrated gives:
(e^u). 2
2e^x as u=x.
Integrating SQRT(x)
SQRT(x)= x^(1/2)
Integrated gives:
(x^3/2)/3/2
Simplyfying
[(2x^(3/2))/3]
Combining both integrals
[2e^x]-[(2x^(3/2))/3] and evaluating between limits of b=10 and a=1
{[2e^x]-[(2x^(3/2))/3]}-{[2e^x]-[(2x^(3/2))/3]}
{[2e^10]-[(2(10)^(3/2))/3]}-{[2e^(1)]-[(2(1)^(3/2))/3]}
{44,052-21.1}-{5.4-0.66)
44,026?
thanks
John