Given:

$\displaystyle ye^y=(x-5y)^3$

Find $\displaystyle \frac{dy}{dx}$, in terms of x and y.

what I tried to do was

Differentiate implicitly wrt x,

$\displaystyle \frac{dy}{dx}(e^y)+\frac{dy}{dx}(y)(e^y)=(3)(x-5y)^2(1-5\frac{dy}{dx})$

$\displaystyle \frac{dy}{dx}(e^y)(1+y)=3(x-5y)^2(1-5\frac{dy}{dx})$

then, i'm stuck in moving all $\displaystyle \frac{dy}{dx}$ to the left-hand side.

any help is much appreciated. thanks.