There is a removable discontinuity at x=-3 -- that is False because there is an open hole? the function is continuous at x = -3

There is a removable discontinuity at x=-1 - is that false because there is an open hole and one closed? there is an essential discontinuity at x = -1

There is a removable discontinuity at x=1 - Also false because one open and closed the discontinuity at x = 1 is removable ... redefining the function to be f(1) = 1 "removes" it