For the first one, take the of both sides so you get:
Now use the fact
Having trouble with a section in my summer assaignment, and my teacher doesnt respond to his e-mails... If someone could help with these few questions, it would help a lot. Thanks.
Solve for y in terms of t:
-2e^(-y/3)=t+4
-t/4)-ln3=ln(20-y)
I know for the 2nd question you need to combine to take the anti-log(I beleive), but I just dont know where. And I have no idea where to start on the first problem.
You put a negative symbol before the (y/3). Could you tell me where you got that from?
Did you get it from the -2e from the begining and moved it to the exponent when you multiplied by the ln?
Also that would make -y/3 = (ln2e) X ((ln t+4))? e would have to be raised by somethig though, so I know that isnt right... but I'm hoping its something along those lines.