Results 1 to 8 of 8

Math Help - absolute extreme values?

  1. #1
    Junior Member
    Joined
    Aug 2007
    From
    Houston, TX
    Posts
    46

    absolute extreme values?

    What does it mean to find the absolute extreme values?

    y= -5coshx + 4sinhx
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by runner07 View Post
    What does it mean to find the absolute extreme values?

    y= -5coshx + 4sinhx
    find the extreme values. the largest one (the absolute max) and the smallest one (the absolute min) are the ones you're after.

    you do remember how to find extreme values right?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Aug 2007
    From
    Houston, TX
    Posts
    46
    do you make it equal to 0 and solve for x?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by runner07 View Post
    do you make it equal to 0 and solve for x?
    you set the derivative = 0 and solve for x, and state the f(x) for that (or those) x's. you also have to check the end points as well
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Aug 2007
    From
    Houston, TX
    Posts
    46
    so itd be...

    y'= 5sinhx + 4coshx =0 ?
    Follow Math Help Forum on Facebook and Google+

  6. #6
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by runner07 View Post
    so itd be...

    y'= 5sinhx + 4coshx =0 ?
    no, \frac {d}{dx} \cosh x = \sinh x
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Junior Member
    Joined
    Aug 2007
    From
    Houston, TX
    Posts
    46
    sorry, but i dont understand how you got that..
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,939
    Thanks
    338
    Awards
    1
    Quote Originally Posted by Jhevon View Post
    no, \frac {d}{dx} \cosh x = \sinh x
    Quote Originally Posted by runner07 View Post
    sorry, but i dont understand how you got that..
    cosh(x) = \frac{e^x + e^{-x}}{2}

    So
    \frac {d}{dx} \cosh x = \frac{d}{dx} \frac{e^x + e^{-x}}{2} = \frac{e^x - e^{-x}}{2} = sinh(x)

    -Dan
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Absolute extreme values of sin and cos
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: April 28th 2010, 10:46 AM
  2. Extreme Values
    Posted in the Calculus Forum
    Replies: 7
    Last Post: November 8th 2009, 03:27 AM
  3. extreme values
    Posted in the Calculus Forum
    Replies: 3
    Last Post: October 6th 2009, 09:30 PM
  4. Absolute Extreme Values
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 28th 2008, 03:27 AM
  5. extreme values
    Posted in the Calculus Forum
    Replies: 1
    Last Post: January 17th 2007, 11:45 PM

Search Tags


/mathhelpforum @mathhelpforum