Limit of power series of discontinuous function

Fn(x)=|Sin^n(X)| is convergent to F(x) where F(x) =1 when x=(m+1/2)pi and F(x) =0when x =otherwise

prove integrate from -infinity to +ve infinity

1. not sure how to integrate a function that is discontinuous at a single point

2 my main confusion is Lim n->inf Fn(x) = 0 which is equal to F(x). Intuitively I can tell the area under sin^n X is not zero even when n->infinity. but I am not sure how to prove it using mathematical formulae

Re: Limit of power series of discontinuous function

What have you tried?

Where are you stuck?

Re: Limit of power series of discontinuous function

Quote:

Originally Posted by

**parklover** Fn(x)=|Sin^n(X)| is convergent to F(x) where F(x) =1 when x=(m+1/2)pi and F(x) =0when x =otherwise

prove

integrate from -infinity to +ve infinity

1. not sure how to integrate a function that is discontinuous at a single point

2 my main confusion is Lim n->inf Fn(x) = 0 which is equal to F(x). Intuitively I can tell the area under sin^n X is not zero even when n->infinity. but I am not sure how to prove it using mathematical formulae

on a set of measure zero, so as far as integration is concerned you can replace it by zero.

CB

Re: Limit of power series of discontinuous function

Quote:

Originally Posted by

**CaptainBlack** on a set of measure zero, so as far as integration is concerned you can replace it by zero.

CB

sorry ,not really understand. you mean set when n->infinity and integrate? How can you get end result not equal 0?

Re: Limit of power series of discontinuous function

Quote:

Originally Posted by

**parklover** sorry ,not really understand. you mean set

when n->infinity and integrate? How can you get end result not equal 0?

Sorry, typo I mean that on a set of measure zero, so:

CB