I think it's correct!
Sorry I don't know any site with more exercices.
Hi
Can somebody tell me if i am correct?
find dy/dx in terms of t for the curve with the parametric representation:
x=(1-t)(1+3t) y=(1+t)(1-3t)
My solution;
x=1 + 2t - 3t^2 y= 1 - 2t - 3t^2
dx/dt= 2-6t dy/dt= -2-6t
dy/dx=(dy/dt)/ (dx/dt)
dy/dx=(-2-6t)/(2-6t)
Can somebody tell me if this is correct-and can somebody recomend a good website with more parametric dy/dx examples-my maths book is not very good.
thanks
John