At this stage, can I simple plug in 1 and 0 into the exponential to get the answer?
By doing so, I would get 4/3. But the model answer is 4/[3xln(5)].
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No, you need to perform the integration first.
How to integrate that exponential function? I thought it remains the same after integration
You can use a small substitution if you want, let therefore:
Originally Posted by Siron You can use a small substitution if you want, let therefore: This agrees with the result that you would get by first rewriting the integrand as , then integrating. Of course, the "rule" for integrating for a > 0 comes from writing it in base e!
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