Evaluate the definite integral

from x=1 to x=4

((x-2))/((square root x)) This is what I did

x^(1/2)-(x)^(-1/2)

(2/3)x^(3/2)-2x^(1/2)

Did I set this up correctly?

Printable View

- August 14th 2011, 10:56 AMhomeylova223The fundamental theorem of calculus?
Evaluate the definite integral

from x=1 to x=4

((x-2))/((square root x)) This is what I did

x^(1/2)-(x)^(-1/2)

(2/3)x^(3/2)-2x^(1/2)

Did I set this up correctly? - August 14th 2011, 10:58 AMMatt WestwoodRe: The fundamental theorem of calculus?
Looks okay to me.

Whoops no, you're a factor of 2 out in the second term. - August 14th 2011, 11:02 AMhomeylova223Re: The fundamental theorem of calculus?
What do you mean factor of 2 out in the second term?

- August 14th 2011, 11:06 AManonimnystefyRe: The fundamental theorem of calculus?
hi homeylova223

he means that you have lost the two from 2x^(-1/2) - August 14th 2011, 11:11 AMhomeylova223Re: The fundamental theorem of calculus?
So would I be left with

(2/3)x^(3/2)-4x^(1/2) ? - August 14th 2011, 11:15 AManonimnystefyRe: The fundamental theorem of calculus?
that is correct but don't forget the integration constant C.

- August 14th 2011, 05:26 PMProve ItRe: The fundamental theorem of calculus?
- August 15th 2011, 02:57 AManonimnystefyRe: The fundamental theorem of calculus?
hi Prove It

sorry i didn't see that it was a definite integral.my mistake.