Evaluate the definite integral

from x=1 to x=4

((x-2))/((square root x)) This is what I did

x^(1/2)-(x)^(-1/2)

(2/3)x^(3/2)-2x^(1/2)

Did I set this up correctly?

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- Aug 14th 2011, 11:56 AMhomeylova223The fundamental theorem of calculus?
Evaluate the definite integral

from x=1 to x=4

((x-2))/((square root x)) This is what I did

x^(1/2)-(x)^(-1/2)

(2/3)x^(3/2)-2x^(1/2)

Did I set this up correctly? - Aug 14th 2011, 11:58 AMMatt WestwoodRe: The fundamental theorem of calculus?
Looks okay to me.

Whoops no, you're a factor of 2 out in the second term. - Aug 14th 2011, 12:02 PMhomeylova223Re: The fundamental theorem of calculus?
What do you mean factor of 2 out in the second term?

- Aug 14th 2011, 12:06 PManonimnystefyRe: The fundamental theorem of calculus?
hi homeylova223

he means that you have lost the two from 2x^(-1/2) - Aug 14th 2011, 12:11 PMhomeylova223Re: The fundamental theorem of calculus?
So would I be left with

(2/3)x^(3/2)-4x^(1/2) ? - Aug 14th 2011, 12:15 PManonimnystefyRe: The fundamental theorem of calculus?
that is correct but don't forget the integration constant C.

- Aug 14th 2011, 06:26 PMProve ItRe: The fundamental theorem of calculus?
- Aug 15th 2011, 03:57 AManonimnystefyRe: The fundamental theorem of calculus?
hi Prove It

sorry i didn't see that it was a definite integral.my mistake.