f is continues in (a,b)

$\displaystyle lim_{x->b^-}f(x_0)=-\infty$

prove that f is not "evenly continues"

??

i dont know the proper term.

basicly we need to prove that there is $\displaystyle \epsilon >0$ so for every $\displaystyle \delta >0$ there is x for which $\displaystyle |y_0-x_0|<\delta$ and $\displaystyle |f(y_0)-f(x_0)|>=\epsilon$

if we choose $\displaystyle \epsilon=1$

also we can use the limit

?