# Math Help - Solving for Y

1. ## Solving for Y

Hello,

I am doing an area of integration question.
y(x) = x^2/3 limits y=1, y=3

y=x^2/3
How do I solve for Y. I have tried a few times and not getting it. I know how to get rid of a power of 2, but power of 2/3 I can't figure it out. It's probably really simple, but I am tired and not getting it.

Any help would be great thanks
Joanne

2. ## Re: Solving for Y

You are trying to find $y$ s.t. $\displaystyle y= \int_{1}^{3} x^\frac{2}{3}~dx$ ?

3. ## Re: Solving for Y

I mean I need to find x out of that. Sorry I just thought about it and worded it wrong.

4. ## Re: Solving for Y

Like this?

$\displaystyle y= x^\frac{2}{3}$

$\displaystyle y= (\sqrt[3]{ x})^2$

$\displaystyle \sqrt{y}= \sqrt[3]{ x}$

$\displaystyle (\sqrt{y})^3= x$