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Math Help - Solving for Y

  1. #1
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    Solving for Y

    Hello,

    I am doing an area of integration question.
    y(x) = x^2/3 limits y=1, y=3

    y=x^2/3
    How do I solve for Y. I have tried a few times and not getting it. I know how to get rid of a power of 2, but power of 2/3 I can't figure it out. It's probably really simple, but I am tired and not getting it.

    Any help would be great thanks
    Joanne
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  2. #2
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    Re: Solving for Y

    You are trying to find y s.t. \displaystyle y= \int_{1}^{3} x^\frac{2}{3}~dx ?
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  3. #3
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    Re: Solving for Y

    I mean I need to find x out of that. Sorry I just thought about it and worded it wrong.
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  4. #4
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    Re: Solving for Y

    Like this?

    \displaystyle y=  x^\frac{2}{3}

    \displaystyle y= (\sqrt[3]{ x})^2

    \displaystyle \sqrt{y}= \sqrt[3]{ x}

    \displaystyle (\sqrt{y})^3=  x
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