I think I understand I have to use ((n+1)(2n+1))/((6)) as the Riemmann sum.
Use limit process find area of the region between graph of the function and the x axis over the indicated interval.
I have
y=-2x+3 from from 0 to 1
I have delta x= 1/n xi= 1i/n
-2(1i/n)+3 times (1/n)
I then have
(-6i)/(n^2) times n(n+1)/(2)
Did I do this correctly?