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Math Help - Evaluating indefinite integral thread number 2?

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    Evaluating indefinite integral thread number 2?

    Can anyone help me find the evaluate the indefinite integral of this function

    1. ((y^2))square root(y)

    My work

    y^2(x^((1/2))

    ((y^3/3))((x^3/2)/((3/2))
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  2. #2
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    Re: Evaluating indefinite integral thread number 2?

    Quote Originally Posted by homeylova223 View Post
    Can anyone help me find the evaluate the indefinite integral of this function

    1. ((y^2))square root(y)

    My work

    y^2(x^((1/2))

    ((y^3/3))((x^3/2)/((3/2))
    Why did you go from y to x?

    Use your laws of exponents to rewrite the question in a form easier to integrate

    Spoiler:
    y^2 \sqrt{y} = y^{2+1/2} = y^{5/2}
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