# Math Help - Evaluating indefinite integral thread number 2?

1. ## Evaluating indefinite integral thread number 2?

Can anyone help me find the evaluate the indefinite integral of this function

1. ((y^2))square root(y)

My work

y^2(x^((1/2))

((y^3/3))((x^3/2)/((3/2))

2. ## Re: Evaluating indefinite integral thread number 2?

Originally Posted by homeylova223
Can anyone help me find the evaluate the indefinite integral of this function

1. ((y^2))square root(y)

My work

y^2(x^((1/2))

((y^3/3))((x^3/2)/((3/2))
Why did you go from y to x?

Use your laws of exponents to rewrite the question in a form easier to integrate

Spoiler:
$y^2 \sqrt{y} = y^{2+1/2} = y^{5/2}$